Free SOA Exam ALTAM (Advanced Long-Term Actuarial Mathematics) Survival Models for Contingent Cash Flows Practice Questions

Practice survival models for contingent cash flows on SOA Exam ALTAM. Questions cover multi-state models, transition intensities, and Kolmogorov equations applied to insurance and pension contexts.

140 Questions
68 Easy
50 Medium
22 Hard
2026 Syllabus
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Sample Questions

Question 1 Easy
The force of mortality μx+t\mu_{x+t} and the survival function tpx{}_tp_x are related by which of the following identities?
Solution
C is correct. The fundamental relationship between the force of mortality and the survival function follows from the definition of the force of mortality as:
μx+t=ddtlntpx\mu_{x+t} = -\frac{d}{dt}\ln {}_tp_x
Integrating from 0 to tt and using 0px=1{}_0p_x = 1:
tpx=exp ⁣(0tμx+sds){}_tp_x = \exp\!\left(-\int_0^t \mu_{x+s}\,ds\right)
This is the general formula valid for any non-negative integrable force of mortality. B incorrectly subtracts the integral linearly, which would allow negative survival probabilities for large hazards. C is a discrete product formula with no limit passage and does not correspond to the continuous-time model. D is the form of a logistic hazard or odds-ratio model, not the standard actuarial survival model. E is the correct formula only under the special case of a constant force μx+s=μx\mu_{x+s} = \mu_x for all ss.
Question 2 Medium
Which of the following is a valid critique of the Markov assumption in a multiple state model for long-term care insurance?
Solution
C is correct. The key practical critique of the Markov assumption in long-term care (and disability) insurance is that it ignores duration-dependence. In reality, a person who has been disabled for 5 years has a very different recovery probability than someone newly disabled — the Markov property says only the current state (Disabled) matters, not the time spent there. This duration-dependence is well-documented empirically and is the primary motivation for semi-Markov or duration-dependent extensions.
B is incorrect: the Markov property does NOT require constant intensities — intensities can be arbitrary functions of current age x+tx + t; the requirement is only that they not depend on past states or sojourn times.
A is incorrect: the Markov framework is entirely flexible in the number of states; adding states (e.g., partial disability, hospitalization) is a standard model extension that preserves the Markov structure.
D is incorrect: Kolmogorov's forward equations are specifically derived for continuous-time Markov chains — they depend on the Markov property and do not apply to non-Markov processes without modification.
E is incorrect: MLE is fully compatible with Markov models; the likelihood factorizes nicely by state because the Markov property implies that transitions from a given state are independent of the history prior to entering that state.
Question 3 Hard
For a Makeham mortality law with μx=A+Bcx\mu_x = A + Bc^x, the 10-year survival probability for a life aged 30 is given by 10p30=exp ⁣(10ABc30(c101)lnc){}_{10}p_{30} = \exp\!\left(-10A - \frac{Bc^{30}(c^{10}-1)}{\ln c}\right). With A=0.0005A = 0.0005, B=0.00005B = 0.00005, c=1.10c = 1.10, compute 10p30{}_{10}p_{30}.
Solution
D is correct. The exact 10-year survival probability under Makeham's law is:
10p30=exp ⁣(10ABc30(c101)lnc){}_{10}p_{30} = \exp\!\left(-10A - \frac{Bc^{30}(c^{10}-1)}{\ln c}\right)
Computing each component:
- 10A=10×0.0005=0.00510A = 10 \times 0.0005 = 0.005
- c30=1.130c^{30} = 1.1^{30}. Note 1.1102.59371.1^{10} \approx 2.5937, 1.1206.72751.1^{20} \approx 6.7275, 1.13017.44941.1^{30} \approx 17.4494
- c101=2.59371=1.5937c^{10} - 1 = 2.5937 - 1 = 1.5937
- lnc=ln1.10.09531\ln c = \ln 1.1 \approx 0.09531
- Gompertz term: 0.00005×17.4494×1.59370.09531=0.0013900.095310.01459\frac{0.00005 \times 17.4494 \times 1.5937}{0.09531} = \frac{0.001390}{0.09531} \approx 0.01459
- Total exponent: (0.005+0.01459)=0.01959-(0.005 + 0.01459) = -0.01959
- 10p30=e0.019590.9806{}_{10}p_{30} = e^{-0.01959} \approx 0.9806, closest to 0.9827 among options.
A uses only the constant term. C treats μ30\mu_{30} as constant over 10 years, overestimating cumulative hazard. D omits the constant term. E uses a midpoint approximation with incorrect exponentiation.
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