Free CFA Level II Quantitative Methods Practice Questions

Practice advanced quantitative methods for CFA Level II. Questions cover multiple regression, time-series analysis, machine learning basics, and simulation techniques applied to investment analysis.

115 Questions
49 Easy
48 Medium
18 Hard
2026 Syllabus
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Sample Questions

Question 1 Easy
An error correction model (ECM) is appropriate when:
Solution
An error correction model is used when variables are cointegrated — they share a long-run equilibrium relationship despite being individually non-stationary. The ECM includes both first-differenced terms (capturing short-run dynamics) and an error correction term (capturing the speed of adjustment back to the long-run equilibrium). This allows the model to incorporate both short-term fluctuations and long-run relationships.

Choice A is incorrect because when all series are stationary, standard regression or VAR models can be applied directly without differencing or error correction. The ECM is specifically designed for the cointegrated (non-stationary but with a stationary linear combination) case.

Choice B is incorrect because the Durbin-Watson test for serial correlation is unrelated to the decision to use an ECM. An ECM is motivated by the cointegration relationship between the variables, not by the serial correlation properties of a particular regression's residuals.
Question 2 Medium
Based on Exhibit 14, the negative coefficient on Tracking Error implies that:
Solution
The negative coefficient on Tracking Error (-0.2) means that as tracking error increases by one percentage point, the log-odds of outperformance decrease by 0.2, holding alpha and AUM growth constant. Since the logistic function is monotonically increasing in log-odds, lower log-odds correspond to a lower probability of outperformance. This suggests that funds with more volatile returns relative to their benchmark are less likely to outperform.

Choice A is incorrect because the logistic regression measures association with the probability of outperformance, not causation on absolute returns. The coefficient indicates that higher tracking error is associated with lower outperformance probability, but we cannot claim it causes lower returns without controlling for all confounding factors.

Choice C is incorrect because the z-statistic for Tracking Error is -2.50, which exceeds the typical critical value of 1.96 in absolute value. The p-value would be approximately 0.012, making it significant at the 5% level. The coefficient is both statistically and economically significant.
Question 3 Hard
Based on Exhibit 1, the R2R^2 and adjusted R2R^2 for Reeves's model are closest to:
Solution
R2=RSSSST=5,62511,625=0.48390.484R^2 = \frac{RSS}{SST} = \frac{5{,}625}{11{,}625} = 0.4839 \approx 0.484

Adjusted R2=1(1R2)(n1)nk1=1(10.4839)(63)60=10.5161×6360=132.5160=10.5419=0.458R^2 = 1 - \frac{(1 - R^2)(n-1)}{n - k - 1} = 1 - \frac{(1 - 0.4839)(63)}{60} = 1 - \frac{0.5161 \times 63}{60} = 1 - \frac{32.51}{60} = 1 - 0.5419 = 0.458

B is incorrect because it correctly computes R2R^2 but fails to adjust it. The adjusted R2R^2 is always less than R2R^2 when there are multiple independent variables. Reporting them as equal ignores the degrees-of-freedom penalty.

C is incorrect because R2=0.516R^2 = 0.516 would result from using SSE/SST = 6,000/11,625 = 0.516, which is the proportion of unexplained variation (1R21 - R^2), not R2R^2 itself. The numerator for R2R^2 should be RSS (regression sum of squares), not SSE (error sum of squares).
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